√(1+(1/1^2)+(1/1^2))+√(1+(1/2^2)+(1/3^2))+√(1+(1/3^2)+(1/4^2))+……+√(1+(1/2007^2)+(1/2008^2))
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/18 21:02:21
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1/√(1+2)
√(a-1)(a^2-1) (-1
(√1-x)^2
√2x+1
2/√3-1
化简1/1+√2+1/√2+√3+...+1/√8+√9
1/1+√2+1/√2+√3+…+1/√2013+√2014=
1/(1+√2)+1/(√2+√3)+1/(√3+√4)+.1/(√2012+√2013)
1/(√2009+√2008)+1/(√2008+√2007)+.+1/(√3+√2)+1/(√2+1)
实数的运算|1-√2|*1/(1-√2)
√2+1,√2-1,1能否构成直角三角形
√2+1是怎样变成 1/√2-1
化简 √[1+1/n ^2+1/(n+1)^2]
√2/1到√20/1 化简√2/1到√20/1 化简
计算(1+√2)(1+√3)(1-√3)(1-√2)我要过程,
(√2+1-2分之1√2)^2
(√2 1-2分之1√2)^2
计算1/(1+√3)+1/(√3+√5)+1/(√5+√7)+^+1/[1/√(2n-1)+√(2n+1)]