(log2)^2-(log4)(log20)+(log20)^2 不用计算机来算出
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2log2为什么等于log4
log2(20)-log2(5)+2log3(2)×log4(3)
log (log2)^2 - (log4)(log20) + (log20)^2
log2(x-2)=log4(5-x)
log2 20-log4 25
log4(log2^x)=log2(log4^x)求log2^x
log4 (x+2) - log2 (x-1) = 是不是要把log4 转换成log2
log2^x=log4^9
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
(log2)^2-(log4)(log20)+(log20)^2 不用计算机来算出
解方程log2(2x)*log4(x/4)=2
log4 (x+2) = log2 (2x-1)
2^(2log2的3次方+log4的16次方 )
(log2 5+log4 125)log3 2/ log根号3 5
log2^根号下2+log9^27+4^(log4^13)
log2 根号2+log9 27+4^log4 13=?
解方程log4(2-x)=log2(x-1)-1
求解log2 (3X+2)-log4 (X)=3