作业帮log2^x=log4^9
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/19 17:46:36
x)O7R&q6IEh"v6UقyF
qF1XճΆ'V$AsRhD $ZęgkW"fh`BF 8Sd
log2^x=log4^9
log2^x=log4^9
log2^x=log4^9
log2^x=log4^9=log2^2 (3^2)=log2^3
所以x=3
as above
log2^x=log4^9
log2^x=log2^2*9
2^x=2^2*9
x=2*9=18
log2^x=log4^9
=>xlog2=9log2^2
=>xlog2=18log2
=>x=18
log2^x=log4^9
log4(log2^x)=log2(log4^x)求log2^x
log2(x-2)=log4(5-x)
log4 (x+2) - log2 (x-1) = 是不是要把log4 转换成log2
log2^x=log4^x,则x=
对数方程 log2^(x-1)=log4^x
对数方程 log2(x+1)-log4(x+4)=1
解方程log4(2-x)=log2(x-1)-1
求解log2 (3X+2)-log4 (X)=3
解log2^(x+1)=log4^(x+13)
log2（x-4）=log4(15-x)+1
解方程log2(2x)*log4(x/4)=2
log4 (x+2) = log2 (2x-1)
解方程：log2(3-x) - log4(x+5) =1
若log2[log3(log4)]=0,求x
求f(x)=log2[log4(log6x)]的定义域
对数方程log2（x-1）=log4 x,如何化成log2（x-1)²?
已知log2^3=a则log4^9=