(2xy+1/5x)^2(-2y+1/2x)^2(-3a-2b)^2(a-b)^2这四道题是完全平方差2步出来就行
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5xy^2-{2x^y-[3xy^2-(xy^2-2x^2y)]/(-1/2xy)}
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²
1.(xy-1)^2-(x+y-2xy)(2-x-y)2.(x+y)(x+y+2xy)+(xy-1)(xy+1)
.(x+y-2)(x+y-2xy)+(xy-1)^2
分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)
5x^2y/-1/2xy*3xy^2
化简!1、(x^2-xy)+xy+y^2 2、3(x^2-xy)-xy+y^2
已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y=
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)
(-2xy+2x+5y)-(3xy+2y-2x)-(x+4y+xy)其中x-y=4xy=-1
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
计算:(1)8x^2y^2*(-3x/4y^5) (2)(x+y)^2/xy-y^2*(y-x)^2/xy+y^2
(-1/2xy)(2/3x^2y-3/2xy^2+6/5y)
(x+y)(x-1)-xy-y^2 怎么因式分解?
计算:(5-xy/x^3-x^2y)/(1-5/xy)^2*(y-x)^3
计算3xy[2xy-x(y-2)+x-1]
{(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)