化简cos^4b-sin^4b
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化简cos^4b-sin^4b
化简 sin^4a-cos^4b
化简COS(a+B)COS(a-B)+sin平方B
化简cos(a+b)cos(a-b)+sin^2b
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
当a=3π/4时,sin(a+b)+cos(a+b)+sin(a-b)+cos(a-b)
sin(a)*cos(a)=4,那么sin(a) cos(b)=?
已知 sin a +sin b =1/4cos a +cos b =1/3求 tan (a+b)
sin(a+B)cos(y-B)-cos(B+a)sin(B-y) 化简
sin(a+B)sin(B-y)-cos(a-B)cos(y-B) 化简
cos(a+b)+cos(a-b)/sin(a+b)+sin(a-b)化简
化简 cos(a-b)cos(a+b)+sin(a-b)sin(a+b).
cos(a-b)cos(a+b)+sin(a-b)sin(a+b)化简,
化简,sin(a+b)cos(r-b)-cos(b+a)sin(b-r)
化简 :sin(a+b)cos(r-b)-cos(b+a)sin(b-r) sin(a-b)sin(b-r)-cos(a-b)cos(r-b)sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 和 sin(a-b)sin(b-r)-cos(a-b)cos(r-b)
matlab符号运算,系数的提取问题.比如一个符号多项式,A*cos(a)*cos(b)+B*sin(a)*sin(b)+C*cos(a)+D*sin(b),这个表达式中的变量包括4个,cos(a)*cos(b)、sin(a)*sin(b)、cos(a)、sin(b),要找到它们的系数A B C D,该怎么找
若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a=1.(不用向量怎么证?)
已知sin^4a/cos^2b+cos^4a/sin^2b=1,求证:sin^4 b/cos^2 a+cos^4b/sin^2a=1