化简cos^4b-sin^4b

化简cos^4b-sin^4b 化简 sin^4a-cos^4b 化简COS(a+B)COS(a-B)+sin平方B 化简cos(a+b)cos(a-b)+sin^2b 由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证：1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a) 当a=3π/4时,sin(a+b)+cos(a+b)+sin(a-b)+cos(a-b) sin(a)*cos(a)=4,那么sin(a) cos(b)=? 已知 sin a +sin b =1/4cos a +cos b =1/3求 tan (a+b) sin(a+B)cos(y-B)-cos(B+a)sin(B-y) 化简 sin（a+B)sin(B-y)-cos(a-B)cos(y-B) 化简 cos(a+b)+cos(a-b)/sin(a+b)+sin(a-b)化简 化简 cos(a-b)cos(a+b)+sin(a-b)sin(a+b). cos(a-b)cos(a+b)+sin(a-b)sin(a+b)化简, 化简,sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 化简 ：sin(a+b)cos(r-b)-cos(b+a)sin(b-r) sin(a-b)sin(b-r)-cos(a-b)cos(r-b)sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 和 sin(a-b)sin(b-r)-cos(a-b)cos(r-b) matlab符号运算,系数的提取问题.比如一个符号多项式,A*cos(a)*cos(b)+B*sin(a)*sin(b)+C*cos(a)+D*sin(b),这个表达式中的变量包括4个,cos(a)*cos(b)、sin(a)*sin(b)、cos(a)、sin(b),要找到它们的系数A B C D,该怎么找 若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a=1.(不用向量怎么证?) 已知sin^4a/cos^2b+cos^4a/sin^2b=1,求证:sin^4 b/cos^2 a+cos^4b/sin^2a=1