若(m^2)-2m+10=6n-(n^2),求{(m^2-n^2)/(m^2+2mn+n^2)+(2/mn)÷(1/m+1/n)^2}÷[1/(m+n)]的值
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若m平方+n平方+2m-6n-6n+10=0求m n的值.
m×m+n×n+2m-6n+10=0,m+n=?赶紧帮忙回答呀,谢谢谢
(1),(-m-n)(-m+n) (2),(-m+n)(m-n)
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满足m^2+n^2+2m-6n+10=0 m、n等于多少
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已知m^2+n^2-6m+10n+34=0,求m-n
m^2+n^2-6m+10n+34=0,求m+n
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(m-n)^3(n-m)^2(m-n)=_____