X(X-1)÷2=15, x2-x-30= (x-6)(x+5)=0 为什么?请详解.
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/01 12:07:48
x)x#Bۍl
Mu*t+t
l4*t45*M5m
dwÓ/o~ًl)3@Άn V j@xjťFֺ { BϦ|e/|4O%]1@YǴ
@Q HO
C[3
#[]S<;Gu\
已知:√x=√a+1/√a求(x2+x-6)/x÷(x+3)/(x2-2x)-[(x-2)+√(x2-4x)]/[(x-2)-√(x2-4x)]的值
分式计算:2x/x2-x-2÷(1-x/x+1)-x2+2x/x2-4
分式计算:2x/x2-x-2÷(1-x/x+1)-x2+2x/x2-4
X(X-1)÷2=15, x2-x-30= (x-6)(x+5)=0 为什么?请详解.
3/x2 -3x+2-1/x-2=1/x2 -x+4/x2 -2x
化简x-1分之x+1-x2-1分之x2-2x÷x2-x-2/x2+2x+1
计算 x 2 - x - 6/(x2-x)+1=0计算 x 2 - x - 6/(x2-x)+1=0x2为x平方,6/(x2-x)为 x平方-x分之6
先化简,再求值 x+3/x2-1 ÷(x+3)(x-1)/x2-2x+1,其中x=2007,
6x+2x2-3x+x2+1 x=-5这道题这么做对不对6x+2x2-3x+x2+16x+2x2-3x+x2+1 =-30+50-(-15)+25+1=61我的意思是我的步骤对不
(x+1)(x2-x+1)+(x-2)(x2+2x+4),其中x=-3/2
(x+2)(x2-2x+4)+(x-1)(x2+x+1),其中x=-三分之二
①x/(x2-1) ·(x2+x)/x2其中x=2 ②(x2-1)/(x2+4x+4)÷(x+1).(x+2﹚/﹙1-x﹚其中x=-3
若2f(x2)+f(1/x2)=x(x>0),求f(x)
解方程 (x2-8x+16) 2x --------------=------- (x2-4x+14) x-2刚刚题没发好(x2-8x+16)/ (x2-4x+14)+(1+2/(x-2))2=2x/(x-2)
2( x2 +1/x2) - 9( x + 1/x) + 14 =
因式分解(x2+x+1)(x2+x+2)-12=
解方程(x2+x)(x2+x-2)=-1
DIvide x3+x2-14x-24 by x+2Solution x2-x-12/)x-2)x3+x2-14x-24x3+2x/-2x2-14x-x2-2x/-12x-24-12x-24/0In this example we see that x+2 is a factor of x3+x2-14x-24,as the remainder is zero.Thus x3+x2-14x-24÷(x+2)=x2-x-12 with zero remainderso x3+x2-14x