若x^2-2x+10+y^2+6y=0,求(2x-y)^2 的值如题
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/04 02:30:46
xQN@=bB
&$]~+\HK{#"
$&<(h+-m!z{7ͬQ-YͤLVQWbZY{5T5ΠG'?ɤ ҦK9ߦ?5;tl=fHŘ] MC-cOKǹh#Cx{ n]hNz-j-Wў)Ω藡WlBkTQNx^O߷H0؏5ᣃu)er4y3R$L/`G!؆ aT|t!dg/
若x^2+y^2-10x-6y+34=0,求(x-y)/(x+y)的值
若x^2+2x+y^2-6y+10=0,则x-y
若x^2+y^2-10x+6y+34=0,则x+y=?
若x²+2x+y²-6y+10=0求x y
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若X^2+Y^2+2X-6Y+10=0,先化简X+Y分之Y^2,分之X-Y分之X-1
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
x,y 满足x(x-2)-y(y-6)=-10,求x,y的值
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^2+y^2/y)^2的值
x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值
已知X*X+Y*Y+6X-8Y+25=0 求(Y/X)+(X/Y)-2=?
求f(x,y)=x+y+7的最大值,使(x,y)满足x+2y≤10,2x+y≥6,y≥0
若X^2+y^2+2x-6y+10=0,求y^2x-x^2011的值
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
已知x^2+y^2--6x--2y+10=0,求x+y/x--y
已知x^2+y^2+6x-2y+10=0,求x+y/x-y的值谢谢