若x^2+y^2-10x+6y+34=0,则x+y=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/19 21:27:29
x){ѽ"H2HРB۬R@i
J[{"}jl3 }ӟvlxgF&PPR3*:f$Aa)(f4
blO?ӞiOv0HA&@RP , x^
若x^2+y^2-10x+6y+34=0,则x+y=?
若x^2+y^2-10x+6y+34=0,则x+y=?
若x^2+y^2-10x+6y+34=0,则x+y=?
x^2+y^2-10x+6y+34=0
得到:(x-5)^2+(y+3)^3=0
所以x=5,y=-3
x+y=5-3=2
2
(x-5)^2+(y+3)^2=0
2
原式可化为(x-5)^2+(y+3)^2=0 所以 x=5 y=-3 x+y=2
若x^2+y^2-10x-6y+34=0,求(x-y)/(x+y)的值
若x^2+y^2-10x+6y+34=0,则x+y=?
已知x、y满足:x^2+y^2+6x-10y+34=0,求y-x的值
若x^2+2x+y^2-6y+10=0,则x-y
若x²+2x+y²-6y+10=0求x y
若X^2+Y^2+2X-6Y+10=0,先化简X+Y分之Y^2,分之X-Y分之X-1
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
x,y 满足x(x-2)-y(y-6)=-10,求x,y的值
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^2+y^2/y)^2的值
若X^2+y^2+2x-6y+10=0,求y^2x-x^2011的值
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
求f(x,y)=x+y+7的最大值,使(x,y)满足x+2y≤10,2x+y≥6,y≥0
x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值
已知X*X+Y*Y+6X-8Y+25=0 求(Y/X)+(X/Y)-2=?
已知x^2+y^2--6x--2y+10=0,求x+y/x--y
已知x^2+y^2+6x-2y+10=0,求x+y/x-y的值谢谢