1+1/2+1/3+1/4+……+1/100=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 09:51:32
x)367bc 6~LC[{"}
l0fɎUO'>gS7<혮Ջ
/?QɎ^ ŲF醍
MRi$ف, ]V
1/(1-1/2)/(1-1/3)/(1-1/4)/……/(1-1/2012)
(1-1/2)×(1-1/3)×(1-1/4)……×(1-1/2008)计算方法
200×(1-1/2)×(1-1/3)×(1-1/4)×……×(1-1/100)=?
计算:(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/10).
(1/2+1/3+1/4+……+1/2013)(1+1/2+1/3+1/4+……+1/2012)-(1+1/2+1/3+……+1/2013)(1/2+……+1/2012)
(1/2+1/3+1/4+1/5+……+1/2007)*(1+1/2+1/3+1/4+……+1/2006)………………计算:(1/2+1/3+1/4+1/5+……+1/2007)*(1+1/2+1/3+1/4+……+1/2006)-(1+1/2+1/3+1/4+……+1/2007)*(1/2+1/3+1/4+^+1/2006)要求简算
计算 (1+1/2)×(1+1/3)×(1+1/4)×……×(1+1/7)×(1+1/8)×计算 (1+1/2)×(1+1/3)×(1+1/4)×……×(1+1/7)×(1+1/8)×(1+1/9)
(1-1/2)(1-1/3)(1-1/4)………………(1-1/99)(1-1/100)
(1/1+2)+(1/1+2+3)+(1/1+2+3+4)+………+(1/1+2+3+………+100)
(1/2+1/3+1//4+…+1/2005)(1+1/2+1/3+1/4+…+1/2004)-(1+1/2+1/3+1/4+…+1/2005)(1/2+1/3+1/4+…+1/2004计算1/2+1/3+1//4+…+1/2005)(1+1/2+1/3+1/4+…+1/2004)-(1+1/2+1/3+1/4+…+1/2005)(1/2+1/3+1/4+…+1/2004)
求和:1/1×2+1/2×3+1/3×4+……+1/n(n+1)
|1/2-1|+|1/3-1/2|+|1/4+1/3|+…+|1/30-1/29|
lim[(1+1/2+1/4+……+1/(2^n)]/[1-1/3+1/9+……+(-1)^(n-1)*(1/(3^(n-1)))]
(1+1/2)*(1+1/3)*(1+1/4)*(1+1/5)*……*(1+1/2002)简便计算
(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/2013)*(1-1/2014)
1/2*1/3+1/3*1/4……+1/41*1/42=?
(1/3+1/4……+1/2006)(1/2+1/3……+1/2006)-(1/2+1/3+……+1/2006)(1/3+1/4……+1/2005)
1/1+2+1/1+2+3+1/1+2+3+4+…+1/1+2+3+…+50