已知函数f(x)=x^2+bx+c(b,c∈R),(1)若f(1)=0,f(3)=0,求f(-1)的值;(2)若函数f(x)在[-2,+∞)上是单调增函数,且c=-b^2,求f(2)的取值范围;(3)若对任意x∈R,恒有f(x)≥2x+b,证明:当x≥0时,f(x)≤(x+c)^2.

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/05 18:47:30
xTN@LHEd"jKK?EiBIXEJJHB;OB8?sϜ9w'yWhO%޴9*roSK |Nm/BWU, uh$va=j卸@w% u`gڒb*orxiV[ ˰ee 6jEXD'%܋r > D# x<ƶR4ۚ){vCX\`A ן9`hŇ bq|}*/eTmEk_9dlhcO%)lN"5KnɤS73HݝşayMJ/bJ$)\ 3^rY1Pred>p;h&%c5ElWtC:_L2T+ҵ㾿ZPw) >IUu~е(?R1_Lu?v