先化简再计算(x^2-1)/(x^2+x)÷[x-(2x-1)/x],其中x是一元二次方程x^2-2x—2=0的正数根
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计算:x(x^2+x-1)-(x^2-x+1)
先化简再计算x²-1/x²+x÷{x-【2x-1/x】},其中X=根号2+1
先化简再计算x²-1/x²+x÷(x-(2x-1)/x),其中X=根号2+1
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