matlab 超越方程e1=(1.09+13.43i)^2e2=2.25k0 =3.2429a= 1.0e-09 [10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1a)+tanh(-e1(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')

来源：学生作业帮助网编辑：作业帮时间：2024/07/21 02:05:27

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matlab 超越方程e1=(1.09+13.43*i)^2e2=2.25k0 =3.2429a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')

matlab 超越方程e1=(1.09+13.43i)^2e2=2.25k0 =3.2429a= 1.0e-09 [10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1a)+tanh(-e1(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')