若x^2+y^2-8x-10y+41=0,求x/y+y/x的值请写我是初一的请用初一的知识解答.的简单一些
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若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
x^2+y^2-8x+10y+41=0求(x+y)^2013
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若x+y-8x-10y+41=0,求x/y+y/x的值
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X^2-Y^2+6X+10Y-30=0 X^2+Y^2-5X-8Y+21=0 X=?Y=?