化简sinπ/12-√3cosπ/12化简sinπ/12-√3cosπ/12
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化简sinπ/12-√3cosπ/12化简sinπ/12-√3cosπ/12
sinπ/12-√3cosπ/12的值
√3cosπ/12-sinπ/12=
若方程12x²+πx-12x=0的两的根分别是α,β,则cosαcosβ-√3sinαcosβ-√cosαsinβ-sinαsinβ=
化简:1,cosπ/8的4次方- sinπ/8的4次方 2,sinπ/12-√3cosπ/12
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简 cos (π/12)+√3sin(π/12)=
(sinπ/24)(cosπ/24)(cosπ/12)
(sinπ/24)(cosπ/24)(cosπ/12)
sinπ/12*cosπ/12=?
求值:sin(π/12)+cos(π/12)
sin(π/12)-cos(π/12)=
cos*π/12—sin*π/12
cosπ/12乘以sinπ/12
计算cosπ/12*sinπ/12
已知α=7/12π,那么cosα√(1-sinα)/(1+sinα)+sinα√(1-cosα)/(1-cosα)=
怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3cosπ/4cosπ/3-sinπ/4sinπ/3
化简√1-2sin(π-3)cos(π+3)