7x+4y-10=0 4x+2y-5=0这是一组二元一次方程,请教高人,我怎么解不开啊~!

x*x+2x+y*y-4y+5=0 x= y= 若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值 已知x*x+4x+y*y-2y+5=0,则x*x+y*y=? 已知|5x-y-8|+(7y-x+2)=0则4x+6y 已知7x+5y/2y-x=3/2,且x≠0,求X/x-4y x*x+y*y-2x+4y+5=0求x, 已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值 .先化简再求值：（2x+y）（2x+y)-(2x-y)平方其中X,Y满足X平方+Y平方-2X+4Y+5=0 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 已知(3x+1)(3x-3)-3x+2)^2=-7,(y+7)(y-7)-y(y-7)=0,求8y^2-5y(-y+3x)+4y(-4y-5/2x)的值 y-3x=2,y-5x=4,y-7x=6,y-9x=8,y-11x=0方程组,无 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? {4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 实数x,y满足|2分之5x-y|+y²-10y+25=0,求代数式1-x-2y分之x-y÷x平方-y平方分之x²-4xy+4y x1:4x-3y=8;y=7-5x;2:2x-7y=8,3x-8y-10=0;3:4x-y=-1;4:5x-10y+15=0;5:2x-4y=6,3x+2y=27;6:3y=x+5,2x+5y=231：2x+3y=7,3x-5y=1;2:3x+5y=5,3x-4y=23;3:3x+5y=5,3x-4y=23;4:5x+y=7,3x-y=1;5:4x-3y=5,4x+6y=14;6:6x+7y=5,6x-7y=19;7:0.5x-3y=-1,-二分之一x+5y=3 已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0 （X+Y)^2 X^2Y+XY^2注：*/* 是分数 {x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0 x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以（x^2+y^2/y)^2的值