-1\2x^2+xy-1\2y^2 (因式分解)
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分解因试(x-1)²-2(x-1)+1 x³y-2x²y²+xy³
.(x+y-2)(x+y-2xy)+(xy-1)^2
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
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1.(xy-1)^2-(x+y-2xy)(2-x-y)2.(x+y)(x+y+2xy)+(xy-1)(xy+1)
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(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
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已知x+y=1,xy=-2,则x²y+xy²-2xy
因式分解(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)
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XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)