如图AB=AC,AE=AF,且∠eab=∠fac,ef=bc.求证四边形ebcf是矩形

如图AB=AC,AE=AF,且∠eab=∠fac,ef=bc.求证四边形ebcf是矩形 已知:如图,AB=AC,AE=AF,且∠EAB=∠FAC,EF=BC.求证:四边形EBCF是矩形. 如图,AB=AC,AE=AF,且角EAB=角FAC,EF=Bc,求证,四边形EBCF是矩形 如图,AB=AC,AE=AF,角EAB=角FAC,EF=BC,求证,四边形EBCF是矩形 已知如图,点a是四边形ebcf内的一点,ab=ac.ae=af且角eab=角fac,ef=bc,求证四边形ebcf是矩形 如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB 已知如图,AE=AC,∠E=∠C,∠EAB=∠CAD,求证:AB=AD 如图,AC=AB,AE=AD,∠EAB=∠DAC,求证：BD=CE 已知：如图,AE=AC,AB=AD,∠EAB=∠CAD 已知：如图,AE=AC,AB=AD,∠EAB=∠CAD已知：如图,AE=AC,AB=AD,∠EAB=∠CAD 求证：①△ABC全等于△ADE；②∠1=∠2 如图,三角形ABC中,AB=AC,且AE=AF,求证EF垂直BC 如图,AD是三角形ABC的中线,AE垂直AC,AF垂直AB,且AE=AC,AF=AB,求证：AD=1/2EF 如图9,AD//BC,AE⊥AD且AE=AD,AF⊥AB且AF=AB.则AC与EF是否相等?为什么? 如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC 如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC的理由 如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE相交于O,请说明∠EAB=∠DAC的理由. 如图,AD∥BC,AD=BC,AE⊥AD,AF⊥AB,且AE=AD,AF=AB,求证：AC=EF. 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:(1)△DAC≌△EAB;(2)BE⊥CD. ,の 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,已知△DAC≌△EAB.求证BE⊥CD