如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB
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![如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB](/uploads/image/z/3741194-2-4.jpg?t=%E5%A6%82%E5%9B%BEAB%E2%8A%A5AC%2CAD%E2%8A%A5AE%2CAB%3DAC%2CAD%3DAE.%E6%B1%82%E8%AF%81%3A%E2%96%B3DAC%E2%89%8C%E4%B8%89%E8%A7%92%E5%BD%A2EAB)
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如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB
如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB
如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB
∵AB⊥AC,AD⊥AE,
∴∠BAC=∠DAE=90°,
∴∠BAC+∠CAE=∠EAD+∠CAE,即∠BAE=∠CAD,
∵AB=AC,AD=AE
∴ΔDAC≌ΔEAB(SAS).
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