a1=1,an-an-1=1/n(n-1),n大于等于2,求an通项公式 a1=2,an-an-1=n,n大于等于2,求an通项公式
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 18:31:26
xPJ@7n6a7l~D@Z,"^,EEm_8c[&yy3hc@EPQ^5xvv+wΆt_QiY{K']%#(
^-%qd3-Z_2kx$~QҭWQ?fpra)dJ(RcK`g%`^i7 0R<[.˘3I3ϺqEm6V=p;mM-V'+
an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么意思?
an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
数列{an}中,a1=1,an+1/an=n/n+2,求an
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
a1=1,Sn=n^2an,求an
已知数列{an}中,a1=1,an+1=3an/(an+3)(N∈N*),求通项an,
已知数列an中,a1=1,an/an-1=n+1/n,n大于等于2,求an
已知A1=1,An=2An-1+n(n>1),求An.
已知A1=1,An+1/An=n/n+1,求An.
已知a1=1,an+1=n乘以an/n+1 求an?
已知数列{an}满足a(n+1)=an+n,a1=1,则an=
an=an-1+2的n次方+n,a1=1,an=?
数列an满足a1=1/3,Sn=n(2n-1)an,求an
数列{an}中,a1=2,an+1=an+ln(n+1/n),求通项公式
数列{an},a1=3,an*a(n+1)=(1/2)^n,求an
a1=1,an+1=an+3^n-n,求an与sn