(1),tana=1/4,则cos2a+sin^2a的值是还有一题
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1+tana/1-tana=2006 则1/cos2a +tan2a
tana=-1/2则sin2a+2cos2a/4cos2a-4sin2a的值是?
求证:1+sin2a-cos2a/1+sin2a+cos2a=tana
证明(1+sin2a-cos2a)/(1+sin2a+cos2a)=tana
求证1+sin2a-cos2a除以1+sin2a+cos2a=tana
证明题:1+sin2-cos2a/1+sin2a+cos2a=tana
tana=3 则1/sin2a+cos2a=?
若tana=2,则(1—sin2a)/cos2a=?
已知tana=2 则cos2a+1=
为什么tanA=1-cos2A/sin2A?
求证:1+sin2a/cos2a=1+tana/1-tana
cos2a/1+sin2a*1+tana/1-tana=?
若(1+tana)/(1-tana)=2009,则1/cos2a+tan2a+1=?
若(1+tanA)/(1-tanA)=2008,则1/cos2A+tan2A=
1-tana/2+tana=1,则:cos2a/1+sin2a=?
若 1+tana/1-tana=2012,则1/cos2a +tan2a=?
若(1+tana)/(1-tana)=2008,则1/cos2a+tan2a=?
若(1+tana)/(1-tana)=2009,则1/cos2a+tan2a=?