∫x^2/(1+^2)dx,∫sin^2xdx计算不定积分

∫sin^2x/(1+sin^2x )dx求解, ∫(1-sin^2( x/2))dx ∫(cosx／1+sin^2x)dx ∫sin^2x(1+tanx)dx ∫1/sin(x/2)dx ∫1+sin^2x/1-cos2x dx∫1+sin^2x/1-cos2x dx ∫x/sin^2(x) dx ∫sin(x) cos^2(x)dx ∫(2/sin^2x)dx= 求∫ sin^2 x/2 dx .. ∫sin(6x)sin(2x)dx=? 求不定积分：∫sin(x^2)dx 求不定积分∫sin(x/2)dx ∫[(sin^2)x]dx求不定积分 ∫sinx/(cosx-sin^2x)dx ∫sin(√2x)dx ∫ 4/sin^2x dx 求∫sin(x^2)dx