求不定积分∫sin(x/2)dx

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求不定积分∫sin(x/2)dx
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求不定积分∫sin(x/2)dx
求不定积分∫sin(x/2)dx

求不定积分∫sin(x/2)dx
∫sin(x/2)dx
=2∫sin(x/2)d(x/2)
=-2cos(x/2)+C

∫sin(x/2)dx ＝＝＝2∫sin(x/2)d(x/2)
==2{-cos(x/2)}+c==-2cos(x/2)+c

∫sin(x/2)dx ＝2*∫sin(x/2)dx/2=-4cos(x/2)+c

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