怎样推出等差数列项的个数的奇偶性质:若共有2n项,S2n=n(an+a(n+1));S偶/S奇=a(n+1)/an;若共有2n+1项,S(2n+1)=(2n+1)*a(n+1);S偶—S奇=-a(n+1);S偶/S奇=n/(n+1).速求,急用

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 01:21:22
xUrVY SYPTx cl#&O%02}e/6Ol2U*q}tR5OG4߂Ԙ=0ze ʢbG<@3!Ux^L]j겂#Y +{E)R# GS m˩(iu#R =DxO|\|F \KZ>U s7&]CA~(n6 }EhYHajI4+>$QkHߏ5AIh#l5,ڳ#Ft~W,X'>z.׳/@4+i:7綾zcr $Q Ul+".TT2nŪI^Uv9IPZ'Z(k7oXـ|5'.ٿPrzwCUh/YVýfO iH?|$v98txjL[ ;8g hNcfa"ВTψ8^" Uȥa{$٢:\7Z,G+C/"YD8zbNLe^jŤ\ \Qsx8ey [b& hO+Ǽ"ݍw4/,fC4odGQ<(p+Ј/xQZJe"Fm)ƶ'>_`0Vz0\ E2Lk} 5D7kB(F٢!th y!:F1\UEYnc3$`uy|!^d