main() { int r,m,n,t; scanf("%d%d",&m,&n); if(m

main() { int r,m,n,t; scanf(%d%d,&m,&n); if(m 求两个数的最大公约数 C语言#includeint main(){int m,n,t,r;scanf(%d,%d,&m,&n);if(m （希望逐步解析）满意则追加分数.#include #include void main(){int m,n,t,p,i,r;scanf(%d%d,&m,&n);if(m C语言程序填空：用辗转相除法求两个整数的最大公约数、最小公倍数.#include void main(){ int n,m,nm,r,t;printf(Enter m,n=?);scanf(%d%d,&m,&n);nm=n*m;if(m #include int ZDGYS(int m,int n) { int r; scanf(%d%d,&m,&n); r=m%n; while(r!=0) { m=n; n=#includeint ZDGYS(int m,int n){int r;scanf(%d%d,&m,&n);r=m%n;while(r!=0){m=n;n=r;r=m%n;}return n;}main(){printf(%d,r);}求m,n的最大公约数 看看哪有 #include void f(int *p,int*q); main() {int m=1,n=2,*r=&m; f(r,&n);printf(%d,%d,m,n);}#include void f(int *p,int*q);main(){int m=1,n=2,*r=&m;f(r,&n);printf(%d,%d,m,n);}void f(int *p,int *q){p=p+1;*q=*q+1;}运行后的结果是A 1,3 B 1,2 说说为 #include int main() { int a[150];int m,n,i,j,t; while(scanf(%d %d,&m ,&n)!=EOF) {printf(#includeint main(){int a[150];int m,n,i,j,t;while(scanf(%d %d,&m ,&n)!=EOF){printf(%d~%d prime include:,m,n);t=0;for ( i=m+1;i int gjs(int m,int n) { int p,t; if(m>n) {p=m; m=n; n=p; } while(n!=0) { t=m%n; m=n; n=t; } return nint gjs(int m,int n){int p,t;if(m>n){p=m;m=n;n=p;}while(n!=0){t=m%n;m=n;n=t;}return n;}#include #include int main(){int a;int b;scanf(%d%d,&a,&b);pri #include int main() { int a[100]; int n,i,j,k,t,m; scanf(%d %d ,&m,&n);#includeint main(){int a[100];int n,i,j,k,t,m;scanf(%d %d ,&m,&n);scanf(%d,&a[i]);for(i=0;i 以下程序的功能：输入两个正整数,求他们的最大公约数.程序如下：main(){int m,n,r,t;printf(Input two number,please! );scanf(%d,%d,&m,&n);if(m0){r=m%n;m=n;___; /*$BLANK2$*/}printf(gcd=%d ,___); /*$BLANK3$*/} 要怎么理解?下面的”辗转相除法”?#include main() {int r,m,n; scanf(“%d%d”,&m,&n); if(m C语言 运算最小公倍数问题#include int fun(int x,int y,int z){ int j,t,n,m;// while (t!=0 || m!=0 || n!=0) { j=j+1; t=j%x; m=j%y; n=j%z; } return j;}main(){ int x1,x2,x3,j; printf(Input x1,x2,x3:); scanf(%d%d%d,&x1,&x c语言分数加减法#include int ggg(int a,int b) { int r; while(r!=0) { r=a%b; a=b;b=r; } return a; } int main() { int n,i,a,b,c,d,h,c1,m,hm,th,tc,cm; scanf(%d,&n); for(i=1;i 用欧几里得算法（辗转相除法）求最大公约数,C语言编程#include #include int main(){int m,n,a,p,q,r;printf(输入两个正整数);scanf(%d,%d,&m,&n);p=m;q=n;if(m VC++简单计算题?求仔细解释.27.有以下程序 #include　void　f(int　*p,int　*q);main(){　int　m=1,n=2,*r=&m;　　f(r,&n);　printf(%d,%d,m,n);}void　f(int　*p,int　*q){p=p+1;*q=*q+1;}程序运行后的输出结果是A)1,3B)2,3C) #include int gcd(int m,int n) { if(m%n==0) printf(%d ,n); else gcd(n,m%n); } main() { i#includeint gcd(int m,int n){if(m%n==0) printf(%d ,n);elsegcd(n,m%n);} main(){int m,n;scanf(%d%d,&m,&n);printf(%d,gcd(n,m%n));}求m整除n 这个程序的结果是怎么得出来的?#includestruct byte{int x;char y;};union{int i[2];long j;char m[2];struct byte d;}r,*s=&r;main(){s->j=0x98765432;printf(%x %x ,s->d.x,s->d.y);} 用C语言实现一个函数,函数功能是返回一个数能被另一个数整除的次数#include#includeint count(int n,int m){int i;int num=0;for(i=n;i>1;i/m){if(i%m==0){num++;}}return num;}int main(){int a;scanf(%d,&a);int t=count(a,2);printf