化简cos(540°-α)sin(α-360°)/sin(-α+180°)cos(180°+α)

化简√3sinα-cosα 化简cos(540°-α)sin(α-360°)/sin(-α+180°)cos(180°+α) 化简sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α) .[1/cos(-α)+cos(180°+ α )]/[1/sin(540°-α)+sin(360°-α)]=tan^3α sinα+cosα 化简 3sinα=2cosα,则 cosα-sinα/cosα+sinα/ cos3sinα=2cosα,则cosα-sinα/cosα+sinα/cosα+sinα/cosα-sinα 求值：（tan10°-√3）×cos10°/sin50° 求证：[sin（2α+β）]/sinα- 2cos（α+β）=sinβ/cosα 化简cosθ+cos（θ+2π/3）+cos（θ+4π/3） 证明：sin（α+β）sin（α-β）=sin^2α-sin^2β 化简sinα^6+cosα^6+3sinα^2cosα^2的结果是 化简：sin^6α+cos^6α+3sin^2α*cos^2α=? 化简3sinα-cosα/sinα+2cosα 化简4sin²α-sinαcosα-3cos²α=0 cos(α+β)cosβ+sin(α+β)sinβ化简RT QAQ 3Q! 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) (1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 （3/2*π 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) 化简：tanα(cosα-sinα)+sinα(sinα+tanα)/1+cosα. sinα=-2cosα,求sin^2α-3sinαcosα+1