设函数f(x)=3sin(wx+π/6),w>0,x属于R,且以π/2为最小正周期 (1)求f(0)? (2)求f(x)的解析式?(3)已知f(a/4+π/12)=9/5,求sina的值 a为α
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 12:04:53
xՒJ@_%˄LN"Z̢YQlZ
袖VU^;Ӕą7Y͜{RQEvl:;U=u[S]:Du5\D/}(d5}߱vWJ>WdM)KѰY 6w o
:`=zr<1٥-i)*D? GdH
p%7td9Xil
SYsN_)_̥$|R)<]x7"g$<.Z095RB
设函数f(x)=sin(wx+t)(-π/2
设函数f(x)=sin(wx+t)(-π/2
设函数f(x)=sin(2wx+π/6)+1/2,(其中0
设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|
设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|
设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|
设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|
老师好:设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|
设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|
设函数f(x)=sin(wx+g)+cos(wx+g) (w>0,|g|
设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值
设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|
设函数f(x)=sin(wx+φ)(w>0,-π/2
设函数f(x)=√3sin(wx-π/3),且f(x)的周期为8,求f(x)的单调增区间
函数f(x)=3sin(wx+ φ)对任意实数x都有f(π/3+x)=f(π/3-x)恒成立,设g(x)=3cos(wx+ φ)+1,则g(π/3)=___.
设函数f(x)=3sin(wx+圆周率/6),w>0,x属于R,且以圆周率/2为小正周期求f(x)解析式
设函数f(x)=3sin(wx+圆周率/6),w>0,x属于R,且以圆周率/2为小正周期求f(x)解析式
设函数f(x)=sin(wx+2π/3)+sin(wx-2π/3)(w>0)的最小正周期为π,求函数的单调区间?