sin(π/4+θ)*sin(π/4-θ)=2/5,则cos2θ=
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化简求值sin^4θ+sin^4(π/3-θ)+sin^4(π/3+θ)
sin^4θ+sin^4(π/3-θ)+sin^4(π/3+θ)化简求值
已知sin(π+θ)
sin(x+π/4)
sin(阿尔法-π/4)
sin(-π/4)求值
sin(π/4+θ)*sin(π/4-θ)=2/5,则cos2θ=
2(sinθ+cosθ)= 2√2sin(θ+π/4)为什么?; (-π/2
提问sin(π/4-θ)=1/3,则sin(π/4+θ)=
化简:2sin(π/4+θ)sin(π/4-θ)=?
证明sinθ+cosθ=根号2sin(θ+π/4)
(cosθ+sinθ)=√2sin(θ+π/4)
已知sinθ=4/5,sinθcosθ
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)我晕,正的还是负的
若sin(θ/2)=4/5,且sinθ
求值:(tan10°-√3)×cos10°/sin50° 求证:[sin(2α+β)]/sinα- 2cos(α+β)=sinβ/cosα 化简cosθ+cos(θ+2π/3)+cos(θ+4π/3) 证明:sin(α+β)sin(α-β)=sin^2α-sin^2β
2sin(x+π/4)sin(x-π/4)=?
sin(x+π/4)sin(x-π/4)等于什么?