(1)1+2+1=4;1+2+3+2+1=_______;1+2+3+4+3+2+1=_______;1+2+3+4+5+4+3+2+1=________;1+2+3+……+100+99+……+1=________;1+2+3+……+n+(n-1)+……+1=________;(2)已知三角形的周长为50,第一条边长为5m+2n,第二条边长的
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(1-1/2^2)(1-1/3^2)(1-1/4^2)……(1-1/100^2)=( )
1.(1+1/2+1/3+1/4)*(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4)=2.(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)=
1-1/2+1/3-1/4+.+1/(2n-1)-1/2n=1/(n+1)+1/(n+2)+1/(3+n).+1/2n
1/2+1/3+1/4=?
1/2-3/1-4/1=
1+(1/1+2)+(1/1+2+3)+(1/1+2+3+4)+(1/1+2+3+4+...+100)=?
填空(填数字)(1/2-1)(1/3-1)=( )×( )=( );(1/2-1)(1/3-1)(1/4-1)=( )×( )×( )=( );(1/2-1)(1/3-1)(1/4-1)(1/5-1)=( )×( )×( )×( )=( );例:(1/2-1)(1/3-1)=( )×( )=( )前两个括号填1/2-1的结果
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15=?
1/2 1/2 1/2 1/2=3 (空白填加减乘除,使等式成立) 1/2 1/2 1/2 1/2=4
(1-1/2)*(1-1/3)*(1-1/4)*...*(1-1/99)*(1-1/100)=
(1-1/2)+(1/2-1/3)+(1/3-1/4)+.+(1/1999-1/2000)=
数列 1+(1+2)+(1+2+3)+(1+2+3+4)+.+(1+2+3+...+2009)=?
一道高中数列求和题1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+...+1/(1+2+3+...99)=?
(1/1×2)+(1/2×3)+(1/3×4)+…+(1/2010×2011)+(1/2012×2013)的值.(提示:1/1×2=1-1/2;1/2×3=1/2-1/3)
1/6【1/4{1/3(1/2X-1)+3}+5】=1
12/(1/2-1/3-1/4)=
1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+.+1/(1+2+3+.100)=?
1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+……+1/(1+2+3+……+100)=?.