(7m^2-4mn-n^2)-2(2m^2-mn+2n^2)计算.
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(5mn-2m+3n)+(-7m-7mn)
(5mn-2m+3n)+(-7m-7mn)
m-n=7 mn=-5求(3m+5n+4mn)-(2n-4n+6mn)
(7m^2-4mn-n^2)-2(2m^2-mn+2n^2)计算.
(7m²-4mn-n²)-(3m²-mn+2n²)求解
[(m+n)^2-4mn][(m-n)^2+4mn]+2(mn)^2
3(m^2n+mn)-4(mn-2m^2n)+mn.要有过程
(2m+n)(4m^2-2mn+n^2)
因式分解m^3-2m^2n+mn^2-4m^2+4mn+4m
已知m-n=4,m、n互为倒数求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4m+mn)的值
m^+2n-mn-2m
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已知m-n=4,mn=2,求多项式(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值.
4-m²n²+2mn
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