log2^x=log4^9

log2^x=log4^9 log4(log2^x)=log2(log4^x)求log2^x log2(x-2)=log4(5-x) log4 (x+2) - log2 (x-1) = 是不是要把log4 转换成log2 log2^x=log4^x,则x= 对数方程 log2^(x-1)=log4^x 对数方程 log2(x+1)-log4(x+4)=1 解方程log4(2-x)=log2(x-1)-1 求解log2 (3X+2)-log4 (X)=3 解log2^(x+1)=log4^(x+13) log2（x-4）=log4(15-x)+1 解方程log2(2x)*log4(x/4)=2 log4 (x+2) = log2 (2x-1) 解方程：log2(3-x) - log4(x+5) =1 若log2[log3(log4)]=0,求x 求f(x)=log2[log4(log6x)]的定义域 对数方程log2（x-1）=log4 x,如何化成log2（x-1)²? 已知log2^3=a则log4^9=