数列an,a1=1,n>=2,an=(根号下sn +根号sn-1)/2,求数列根号sn为等差数列,及an通项我想问的是,“(2)由(1)得√Sn=1+(n-1)/2=(n+1)/2”这里是如何得出的?
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/09 23:54:13
xRAN@
KZ 8e`\O 4&*5ڸj-VK@Y
mW&
uxJLRճ)oɑ4C"1QStmNJ .,<0Gs\.gE <jBuf<-/1vv[]{nwh]$3uf".vt9!(
YU嗌nHpSGAr+Y, AA',퉤lJZN6!;j.**lѠ]L~+6L
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
数列{an}中,a1=1,an+1/an=n/n+2,求an
设数列{an}中,a1=2,an+1=an+n+1,则通项an=?
在数列an中,a1=2 an+1=an+3n则an=
数列an集合中,a1=2,an+1=an+(2n+1),求an.
数列{an}中,a1=35,an+1-an=2n-1,求an
已知数列an,a1=1 an+1-an=2的n次幂求an
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列{an},a1=2,an+1(下标)=an下标+n+1 求通项an下标
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列{an}满足a1=2,a(n+1)=2an+n+2,求an
数列an满足a1=1/3,Sn=n(2n-1)an,求an
数列{an}中,a1=2,an+1=an+ln(n+1/n),求通项公式
数列{an},a1=3,an*a(n+1)=(1/2)^n,求an
数列an,a1=1.an+1/an=n+2/n,求通项公式,
已知数列{an}中,a(n+1)=an+2^n,a1=3,求an