y-2x+1是4xy-4x^2-y^2-k的一个因式,则的k值是?
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(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
x-y/x^2+xy除以xy-x^2/x^2y^2-x^4*1/x-y
计算:2xy/(x+y)².(x+y)/4y
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²
分解因式x^2y+x^2y+2xy^2-4xy^3是x^3y+x^2y+2xy^2-4xy^3
计算:(4xy(x-y)^-1+(x(y^-1)-(x^-1)y)/((x^-1)+(y^-1)))*(x+y)^-2
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
1-2/x+y=xy,4y+6x=xy.求xy的解?
(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)
因式分解 x-xy+3y-3x 2x+xy-y-4x+5y-6
(x²-4y²)÷(2x+y)/xy×1/x(2y-x)(2x+y)/xy 1/x(2y-x) 都是一项
下列因式分解中,正确的是:.A.-2x^3-3xy^3+xy=-xy(2x^2-2y^2+1).B.-x^2-y^2=-(x+y)(x-y)C.16x^2+4y^2-16xy=4(2x-y)D.x^2)y+2xy+4y=y(x+2)^2
已知1/x - 1/y = 2,求3x+7xy-3y / 2x-3xy-2y的值1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/71/x-1/y=2到(y-x)/xy=2 是怎么变化的..
x-2xy-1+4y²