化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2

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化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2

化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
=[4xy/(x-y)+(x/y-y/x)/(1/x+1/y)]/(x+y)^2
=[4xy/(x-y)+((x^2-y^2)/xy)/((x+y)/xy)]/(x+y)^2
=[4xy/(x-y)+(x-y)]/(x+y)^2
=[(4xy+(x-y)^2)/(x-y)]/(x+y)^2
=[(x^2+2xy+y^2)/(x-y)]/(x+y)^2
=[(x+y)^2/(x-y)]/(x+y)^2
=1/(x-y)

[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
=[4xy/(x-y)+(x/y-y/x)/(1/x+1/y)]/(x+y)^2
=[4xy/(x-y)+((x^2-y^2)/xy)/((x+y)/xy)]/(x+y)^2
=[4xy/(x-y)+(x-y)]/(x+y)^2
=[(4xy+(x-y)^2)/(x-y)]/(x+y)^2
=[(x^2+2xy+y^2)/(x-y)]/(x+y)^2
=[(x+y)^2/(x-y)]/(x+y)^2
=1/(x-y)

化简4xy-y-xy+x 化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2 化简xy-1-x+y 化简[x-y+4xy/(x-y)][x+y-4xy/(x-y)] 化简:(x+y-4xy/x+y)*(x-y-4xy/x-y)= (x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1) 化简：3x^2-[5xy-(x^y-3xy)+4x^2y-8xy] xy-1+x-y 化简2(x²y+xy)-3(x²y-xy)-4x²y 化简3（x²y+xy)-4(x²y-xy)-5x²y, x-y/x^2+xy除以xy-x^2/x^2y^2-x^4*1/x-y 化简1-x-y/x+2y÷x^2-y^2/x^2+4xy+4y^2 化简1— x-y/x+2y÷x²-y²/x²+4xy+4y² 化简(2x+y)^2-(2x-y)(2x+y)-4xy其中x=2010,y=-1 XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2) 已知xy>0,证明xy+xy/1+x/y+y/x>=4 1-2/x+y=xy,4y+6x=xy.求xy的解? xy>0,证xy+1/xy+x/y+y/x>=4