5^log30*3^log2=15
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/11 01:58:39
x)3O762F6IEXDlTm
ApQ-2(Ov*0 L5Nꁨ>lx{)$ف JwDA
5^log30*3^log2=15
log2 3=a ,log3 5 =b 试用a,b表示log30 45
log2 3=a,log3 5=b,试用a,b 表示log30 45
已知log2 3=a,log5 2=b,用a,b表示log30 12
log12 27=a,求log6 16?log14 7=a ,log14 5=b,求log35 28?lg5=a,log2 6=b,求log3 2,log4 0.12?log6 15=a,log5 18=b,求log30 50?
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
log18 9=a,log18 5=b,求log30 36=?要求写出解题思路,
已知log18 9=a,18^b=5用a,b表示log30 36
log2^5+3=
log2 3/log2 5等于log2 3-log2 5么?
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
已知log18 9=a,18的b次幂=5,求log30 36的值
设log2 3=a,log2 5=b,则log9 15=?
求值:log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的?
LOG2^3=A,LOG2^5=b,则log2^9/5值是多少
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
(log2 9)/(log2 8) = 2/3(log2 3)
log2^(4^7*2^5)+log2^6-log2^3