log8(9)除以log2(3)中间有点不太熟悉啊。
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log8(9)除以log2(3)中间有点不太熟悉啊。
log8(9)*log2(3)
log8的27除以log2的3
(log8 9/log2 3)=?
求(log2^3+log8^9)
log8 9除以log2 3是多少(注意9在8上,3在2上)
log8ˇ9除以log2ˇ3 等于?ˇ为上标符号
log8^9/log2^3的值是
已知log2^3=a.则log8^3= log8^9=
求值:log8(底数)9/log2(底数)3 (过程)
log8的9次方/log2的3次方=
计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号3计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号32
log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9
化简:(log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根
( log8^9 )/( log2^3 )求值其中2和8是底数 3和9是真数
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))