作业帮(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/28 09:09:47
xJ@_%
Bf2Ent V&NmTW
].܈අ/Ӧ+8ie[99sU$de9ը H LmFzt\4`ðw:> 'B{t2n {Ǣj{LZdV[~*c;om;"HqٌV G^ c١#<ߥ!xM0V
AWeQ!WY`Ws2cBq(Cu8ii!ױF9
B,*IYOM *W) Ei` x.G4(ݲɷ1̽dM KH~Gb0(-vl 4]7: {28JKbS@yE
(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根
(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根
(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根
不知道是不是图片上的这个意思.
log2^n 3^n=log2 3，log9 32=5/2log3 2，
(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32=[nlog2 3]*[5/2log3 2]=5n/2
原式=（5n/2）^(1/n)
log8(9)*log2(3)
计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32
log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9
化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)
(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根
(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根
(log8 9/log2 3)=?
求(log2^3+log8^9)
log4 243 - log8 729=?log4 12 - log2 6=?
求值：【log2（3）+log4（9）+log8（27）+log16（81）+log32（243）】—5log2（3/2)
求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64)
log8^9/log2^3的值是
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
利用换底公式求值：1.log2 25 ×log3 4 ×log5 9 2.（log4 3+log8 3）（log3 2+log9 2）
(log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方
(log8^27)/(log4^9)的值
log4(3)+log8(3) 怎么算
log4(3)+log8(3) 怎么相加?