求 y=x-√1-2x y=2x+√1-2xy=1-x/2x=5的值域
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/05 11:58:51
xJ@_%'%Y-EJzQ]!?SJ(X˄lofijA\;XvaR\kbd:|m:ܸ#G77wXumkmCt4Fv[N(~w'$TAkKp;]l
MabuPVuJ
f\J*856}~hhV?mUO~#[fP+ `-@(2|-9Fepo 9jpչ_=~}Mԍtp;CwW&Ey¤e.eb4@Q!AN,AƘvCw@Gh{u ̀NF_fV'&,@+J0ioݡ
y=arcsin(x/√1+x^2),求y'
y=ln(x+√x^2+1),求y
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
x+2y=2x+y+1=7x-y 求:2x-y?
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
若x*x+y*y=x+y-1/2,求x,y的值如题
x+y =√2,x平方+y平方=1求x/y=y/xx+y =√2,x平方+y平方=1求x/y+y/x
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
x+y=1,xy=-1/2,求x(x+y)(x-y)-x(x+y)2
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
求值域 y=(x²-1)/(x²+x+1); y=2x-3+√(13-4x); y=(3x+2)/(x-1)
求值域 y=(x²-2)/(x²+x+1); y=2x-3+√(13-4x); y=(3x+2)/(x-1)
求下列式子dy/dx (1) x^2y-x+y=0;(2) x√y =y-11
y=ln(x-√x^2+a^2)-arcsin(a/x) 求y' y=ln(x+√1+x^2) 求y‘
求导数y=xln(x+√1+x^2)-√1+x^2y=xln(x+√1+x^2)-√1+x^2 求y'
已知4x²+y²-4x-6y+10=0求(2/3x(√9x)+(y²√x/y³)×(x²√1/x×5x√y/x)的值
已知4x²+y²-4x-6y+10=0求(2/3x(√9x)+(y²√x/y³)-(x²√1/x-5x√y/x)的值