已知asinθ+bcosθ=c,bsinθ+acosθ=d,求证:(ac-bd)²+(ad-bc)²=(a²-b²)²
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已知asinθ+bcosθ=c,bsinθ+acosθ=d,求证:(ac-bd)²+(ad-bc)²=(a²-b²)²
已知asinθ+bcosθ=c,bsinθ+acosθ=d,求证:(ac-bd)²+(ad-bc)²=(a²-b²)²
x=asin(c)+bcos(c) y=acos(c)+bsin(c) (0
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已知实数a,b均不为0,asinα+bcosα/acosα-bsinα=tanβ已知实数a,b均不为0,(asinα+bcosα/acosα-bsinα)=tanβ且β-α=π/6则b/a=?谢谢越快越好
已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值