设函数f(x)=1/3x^3+ax^2+5x+6在区间[1,3]上是单调函数,则实数a的取值范围是主要是没看懂别人回答的"当f'(x)>=0时,g(根号5)<=g(x)<=a"和"当f'(x)
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/21 19:18:07
xՑN@߅mSOm_@fhk
!0S_mc|]4Spi%"`{{l%Qse#t+|H
}Ux9J~X@w`>Z-xt
S0.창Kob1M?~W3ߋ"xSPqm3x4M:,Y,0/""ǐ&37lqYã)>c&,3%{g%$VC'oJ*bvnuU{CL
Ј~T
设函数f(x)=x^3+ax^2-9x-1(a
设函数f(x)=x^3+ax^2-9x-1(a
设函数f(x)=x^3+ax^2-9x-1(a
设函数f(x)=x^3+ax^2-9x-1(a
急设函数f(x)=2{x}^{3}+ax-2,已知f(x)
设函数f(x)=-1/3x^3+2ax^2+1/3a(0
设函数f(x)=ax^2-2x+3,对于满足1
设函数f(x+1)=ax+1,且f(2)=3,则a=
(x-3)(2x-1)设函数f(x)=ax^³+b,已知f(1)=0,则
设函数f(x)=ax+2,不等式|f(x)|
已知函数f(x)=x^3+ax^2+x+1,设函数f(x)在区间(-2/3,-1/3)内是减函数,求a的范围?
设函数f(x)=1/3ax^3+bx^2+cx(a
设函数f(x)= -1/3x^3+2ax^2-3a^2x+a/3(0
设函数f(x)=-1/3x~3+2ax~2-3a~2x+1(0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+1(0
设函数f(x)=1/3x^3-1/2ax^2-2a^2x+1(a
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0