设tanx=3tany(0
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设tanx=3tany(0
已知tanx=3tany(0
已知tanx=3tany(0
高手进tanx+tany/tanx-tany=3/2 求tanx/tany?
已知tanx=1/3,tany=-2,且0
若0≤x-y<π/2,且tanx=3tany,则x-y的最大值为?tan(x-y)=(tanx-tany)/(1+tanxtany)=2tany/(1+3tan^2y)=2/(1/tany+3tany)为什么是小于等于这个呢?不懂 ≤2/2√(1/tany*3tany)
求证.(tanx+tany)/(tanx-tany)=(sinx+siny)/(si求证.(tanx+tany)/(tanx-tany)=(sinx+siny)/(sinx-siny)
已知:tanx=1/3,tany=-2.求tan(x+y)若0度
已知tanx=2,tany=3,x,y∈(0,π/2),求x+y.
已知0小于X,y小于90度,tanx=3tany,求证x-y
如果实数x,y满足|tanx|+|tany|>|tanx+tany|,且y∈(π,3π/2),则|tanx-tany|等于
tan(x+y)=tanx+tany吗
2.若0<y≤x<∏/2且tanx=3tany,则x-y=?
设m为实数,tanx和tany是方程mx^2+(2m-3)x+(m-2)=0的两个实数根,求tan(x+y)的最小值
证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))thanks
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)
tan(x+y)=0是tanx+tany=0成立的什么条件
tanx=1/2,x=?tany=1/3,y=?