证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))thanks

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证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))thanks
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证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))thanks
证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))
thanks

证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))thanks
利用tanx=sinx/cosx的定义,左边的一定可以化为sinx和cosx的式子
同理右边的可以分解为sinx和cosx的式子
二者一定相等