cos(兀/8)^4-sin(兀/8)^4得于多少
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计算sin兀/8cos兀/8
三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)
sin^2(兀/8)-cos^2(兀/8)
2cos+7tan兀-4sin二分之3兀-8cos二分之兀等于
d/dx sin^8(cos(4x))
cos(兀/8)^4-sin(兀/8)^4得于多少
化简4sin派/8*cos派/8*(cos^2派/8-sin^2派/8)
证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)]
8sin(45+a)sin(45-a)=1,sin^4a-cos^4a=
cosA+cos^2A=1,sin^2A+sin^4A+sin^8A
已知a属于(0,π/2),且2sin^2 a-sin a cos a-3cos^2 a=0,求SIN(a+兀/4)/SIN 2a+COS 2a+1的值^2表示平方 答案是8分之根号26
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
cos(-17兀/4)-sin(-17兀/4)=
cos^6(π/8)-sin^6(π/8)=求值,[cos^2(π/8)-sin^2(π/8)][cos^4(π/8)+sin^4(π/8)+cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-[sin^2(π/4)]/4]==7√2/16
若x=兀/12 sin^4-cos^4=
sin[兀/3 + arc cos(-1/4)] 的值
cos(兀-2a)/sin(a-兀/4)=-跟号2/2求cos(a)+sin(a)
sin^4π/8 +cos^4π/8