sin(a+π/3)+sina= - 4根号3/5,则cos(a+2π/3)怎么求》
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sinA=3sin(2π/3-A) SINA=?sinA=3sin(2π/3-A) SINA=?答案是-3√3cosA
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
已知tan{π/4+a}=3,求sina*sin(3π /2 +a)-sin^2a+1的值
sin(6/π-a)=1/3 sina=
已知sin(π+a)=1/3,则sina=
为啥sina+cosa=√2sin(a+π/4)
sin(3π-a)=sina?三角函数诱导
1- sin(2π/3 - a)/sina
sin(a-pia/4)=3/5,求sina
已知sina=1/3,则sin(a+π/4)cos(a+π/4)
设(sina)^2-sina-2(cosa)^2=0,求sin(a-3π/2)
已知tan(π-a)=2,求值:(1)2sin+2cosa/7sina+cosa(2)sina*cosa(3)4cosa^2+3sina^2
假如令θ=a,则sin(3π+θ)=-sinθ=-sina=1/4,sina=-1/4,为什么的?
化简sin(π/4+a)cosa-sin(π/4-a)sina=
sin(4分之π+a)sin(4分之π-a) sina=二分之一
证明sinA+sin(A+2π/3)+sin(A-2π/3)=0
证明sinA+sin(A+2π/3)+sin(A-2π/3)=0