f(A,B)=sin^2(2A)+cos^2(2B)-根号3sin2A-cos2B+2
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.若f(x)=sinα-cosx,则f′(α)等于 A.sinα B.cosα C.sinα+cosα D.2sinα
cos^2a-cos^2b=m,那么sin(a+b)sin(a-b)=?
证明sin(A+B)sin(A-B)=cos^2B-cos^2A
证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1
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求证cos(a+b)cos(a-b)=cos^2a-sin^2b
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由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
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化简cos(a+b)cos(a-b)+sin^2b
【(sin a+cos a)/(sin a-cos a) 】=3,tan (a-b)=2,tan (b-2a)=?
Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2
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求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a
matlab解方程组方程组1:(m/2-n*sin(c/2)+e*cos(f))^2+(h+n*cos(c/2)-e*sin(f))^2-(m/2-n*sin(c/2+d)+e*cos(f-b))^2-(h+n*cos(c/2+d)-e*sin(f-b))^2=0;方程组2:(m/2-n*sin(c/2)+e*cos(f))^2+(h+n*cos(c/2)-e*sin(f))^2-(m/2+e*cos(a+f)-n*sin(c/2-d))^2-(h
已知f(a)=sin (π-a )cos(2π-a )cos(-a+3/2π)/cos (π/2-a )sin (-π-a)