f(A,B)=sin^2(2A)+cos^2(2B)-根号3sin2A-cos2B+2

.若f(x)=sinα－cosx,则f′(α)等于 A.sinα B.cosα C.sinα+cosα D.2sinα cos^2a-cos^2b=m,那么sin(a+b)sin(a-b)=? 证明sin(A+B)sin(A-B)=cos^2B-cos^2A 证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1 求证cos(a+b)cos(a－b)=cos^2b－sin^2a 求证cos(a+b)cos(a-b)=cos^2a-sin^2b sin(a-b)*cos a-cos(a-b)*sin a=1/5,则cos 2b的值是 由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证：1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a) f(x)=a(cos^2 x+sin xcos x)+b,求当a 化简cos(a+b)cos(a-b)+sin^2b 【(sin a+cos a)/(sin a-cos a) 】=3,tan (a-b)=2,tan (b-2a)=? Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2 已知f(a)=[sin(TT-a)cos(2TT-a)tan(-a-TT)]/[sin(-a-TT)],化简f(a), a,b为锐角,cos(b+a)=sin(a-b),若f(a)=sin(a+π/4)+cos(a-π/4),求f(π/2-a)的值.这是两角的和差公式吗？还没学呢。 2道高一三角函数题1、f(sin x)=2-cos 2x,求f(cos x)的解析式2、sin b=1/3,sin(a+b)=1,求sin(2a+b)的值 求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a matlab解方程组方程组1：(m/2-n*sin(c/2)+e*cos(f))^2+(h+n*cos(c/2)-e*sin(f))^2-(m/2-n*sin(c/2+d)+e*cos(f-b))^2-(h+n*cos(c/2+d)-e*sin(f-b))^2=0;方程组2：(m/2-n*sin(c/2)+e*cos(f))^2+(h+n*cos(c/2)-e*sin(f))^2-(m/2+e*cos(a+f)-n*sin(c/2-d))^2-(h 已知f(a)=sin (π-a )cos(2π-a )cos(-a+3/2π)/cos (π/2-a )sin (-π-a)