2/1x-2/3y=--1 2x+y=3
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 08:39:45
x}N0_%s+c5qPUJPKPDKZZxi'^*}02ID8Y+⩺;_Qo&?S0_8{wud62)D윲/`S +{:i_݆$ec=QON:-/)Pu?LVX/X+ZU ]mZ#
a
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
二元一次方程 :2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y
(x-y)^2+(x+y)(x-y) 其中 X =3 Y=-1
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
已知:2x+y=6,x-3y=1 求7y(x-3y)(x-3y)-2(3y-x)(3y-x)
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
[3x^2-(x+y)(y-x)][2(-x-y)(y-x)+2x^2+3y^2],其中x=-2分之1,y=1.5
[(y-2x)(-2x-y)+4(x-2y)平方]/3y,其中x=1,y=-3
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3