已知函数f(x)=2x+3/3x,数列{an}满足a1=1,an+1=f(1/an),n为正整数(2)令Tn=a1a2-a2a3+a3a4-a4 a5+……-a2n a2n+1,求a2n-1-a2n+1及Tn

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