sinx+siny=1/3 ,cosx+cosy=1/2,求tan(x+y)的值.
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sinx+siny=1/3,则siny-(cosx)^2的最大值为?最小值为?
已知sinx+siny=1/3求siny-(cosx)^2的最小值和最大值
已知sinx+siny=1/3求siny-(cosx)^2的最小值
已知1+cosx-siny+sinx*siny=0,1-cosx-cosy+sinx*cosy=0.求Sinx.
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cosx+cosy=1,则sinx+siny的范围
sinx-siny=-√3/3 cosx-cosy=-1/3 则cos(x-y)
sinx-siny=1/3,cosx-cosy=2/3,sin(x+y)=?
cosx+cosy=1/2,sinx-siny=1/3,则cos(x+y)=?
cosx-cosy=1/2,sinx-siny=1/3,sin(x+y)=RT
已知cosx+cosy=1/2,sinx-siny=1/3,则cos(x+y)=
sinx+cosy=1/3 cosx+siny=1/6 则sin(x+y)=?RT
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cosx-cosy=4/1,sinx-siny=3/1求cos(x-y)
sinx+cosy=1/3 cosx+siny=1/6 则 sin(x+y)?
sinx+siny=-1/3 cosx+cosy=1/2,求sin(x+y)的值.