已知(x+y)/z=(x+z)/y=(y+z)/x=2,且xyz≠0,则分式(x+y)(x+z)(y+z)/xyz的值为?
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(x+y-z)(x-y+z)=
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已知:(x+y-z)/z=(x-y+z)/y+(y+z-x)/x,且xyz≠0,求代数式[(x+y)(y+z)(x+z)]/xyz的值已知:(x+y-z)/z=(x-y+z)/y=(y+z-x)/x,且xyz≠0,求代数式[(x+y)(y+z)(x+z)]/xyz的值 题目中写错个等号,汗...
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
(y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值